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Viewing questions 21-30 out of questions

Questions # 21:

Which three statements are true regarding indexes?

Options:

A SELECT statement can access one or more indices without accessing any tables.

A table belonging to one user can have an index that belongs to a different user,

When a table is dropped and is moved to the RECYCLE BIN, all Indexes built on that table are permanently dropped.

A UNIQUE index can be altered to be non-unique.

An update to a table can result in no updates to any of the table's indexes.

An update to a table can result in updates to any or all of the table's indexes.

Questions # 22:

Examine this SQL statement:

Question # 22

Which two are true?

Options:

The subquery is executed before the UPDATE statement is executed.

All existing rows in the ORDERS table are updated.

The subquery is executed for every updated row in the ORDERS table.

The UPDATE statement executes successfully even if the subquery selects multiple rows.

The subquery is not a correlated subquery.

Answer

A, C

Explanation

The provided SQL statement is an update statement that involves a subquery which is correlated to the main query.

A. The subquery is executed before the UPDATE statement is executed. (Incorrect)

This statement is not accurate in the context of correlated subqueries. A correlated subquery is one where the subquery depends on values from the outer query. In this case, the subquery is executed once for each row that is potentially updated by the outer UPDATE statement because it references a column from the outer query (o.customer_id).

B. All existing rows in the ORDERS table are updated. (Incorrect)

Without a WHERE clause in the outer UPDATE statement, this would typically be true. However, the correctness of this statement depends on the actual data and presence of matching customer_id values in both tables. If there are rows in the ORDERS table with customer_id values that do not exist in the CUSTOMERS table, those rows will not be updated.

C. The subquery is executed for every updated row in the ORDERS table. (Correct)

Because the subquery is correlated (references o.customer_id from the outer query), it must be executed for each row to be updated in the ORDERS table to get the corresponding cust_last_name from the CUSTOMERS table.

[Reference: The behavior of correlated subqueries is detailed in the Oracle Database SQL Language Reference, which explains that a correlated subquery is evaluated once for each row processed by the parent statement (Oracle Database SQL Language Reference, 12c Release 1 (12.1))., D. The UPDATE statement executes successfully even if the subquery selects multiple rows. (Incorrect), The subquery inside the SET clause must return exactly one value for each row to be updated. If the subquery returns more than one row for any outer row, the UPDATE statement will result in an error (specifically, an "ORA-01427: single-row subquery returns more than one row" error)., E. The subquery is not a correlated subquery. (Incorrect), This is incorrect because the subquery references the o.customer_id column from the ORDERS table, which makes it a correlated subquery., The correct answers are A and C. The subquery is a correlated subquery because it references the ORDERS table's customer_id in its WHERE clause. It is executed for each row to be updated since it depends on values from the outer query (the o.customer_id). It's important to note that although the statement A is marked incorrect based on the typical behavior of correlated subqueries, in some cases, Oracle's optimizer may unnest the subquery and execute it beforehand if it determines that it's more efficient and the result is the same. However, this doesn't change the nature of the query being a correlated subquery., , ]

Questions # 23:

Examine the description of the CUSTOMERS table:

Which three statements will do an implicit conversion?

Options:

SELECT * FROM customers WHERE insert_date=DATE’2019-01-01’;

SELECT * FROM customers WHERE customer_id=’0001’;

SELECT * FROM customers WHERE TO_DATE(insert_date)=DATE’2019-01-01’;

SELECT * FROM customers WHERE insert_date’01-JAN-19’;

SELECT * FROM customers WHERE customer_id=0001;

SELECT * FROM customers WHERE TO_CHAR(customer_id)=’0001’;

Questions # 24:

Which two statements about INVISIBLE indexes are true?

Options:

an INVISIBLE Index consumes no storage

You can only create one INVISIBLE index on the same column list

The query optimizer never considers INVISIBLE Indexes when determining execution plans

You use AlTER INDEX to make an INVISIBLE Index VISIBLE

All INSERT, UPDATE, and DELETE statements maintain entries in the index

Questions # 25:

Examine the description of the CUSTOMERS table:

Question # 25

Which three statements will do an implicit conversion?

Options:

SELECT * FROM customers WHERE TO_ CHAR (customer_ id) = '0001';

SELECT * FROM customers WHERE customer id = '0001';

SELECT * FROM customers WHERE customer_ id = 0001;

SELECT FROM customers WHERE insert date = '01-JAN-19';

SELECT. FROM customers WHERE insert_ date = DATE *2019-01-01';

SELECT. FRON customers WE TO DATE (Insert _ date) = DATE ‘2019-01-01’;

Questions # 26:

Which three statements are true about a self join?

Options:

It must be an inner join.

It must be an equijoin.

The query must use two different aliases for the table.

The on clause can be used.

The on clause must be used.

It can be an outer join.

Questions # 27:

Which three actions can you perform on an existing table containing date?

Options:

Add a new column as the table's first column.

Define a default value that is automatically inserted into a column containing nulls.

Add a new NOT NULL Column with a DEFAULT value.

Change a DATE Column containing data to a NUMBER data type.

Increase the width of a numeric column.

Change the default value of a column.

Questions # 28:

Which two statements are true regarding non equijoins?

Options:

The ON clause can be used.

The USING clause can be used.

The SQL:1999 compliant ANSI join syntax must be used.

Table aliases must be used.

The Oracle join syntax can be used.

Questions # 29:

Question # 29

Which two queries only return CUBE?

Options:

SELECT shape FROM bricks JOIN boxes ON weight >= min_weight AND weight < max_weight;

SELECT shape FROM bricks JOIN boxes ON weight > min_weight;

SELECT shape FROM bricks JOIN boxes ON weight BETWEEN min_weight AND max_weight;

SELECT shape FROM bricks JOIN boxes ON weight < max_weight;

SELECT shape FROM bricks JOIN boxes ON NOT (weight > max_weight);

Questions # 30:

Examine this statement:

Question # 30

Which two things must be changed for it to execute successfully?

Options:

The word CONSTRAINT in the foreign key constraint on DEPT_ID must be changed to FOREIGN KEY.

The foreign key constraint on DEPT_ID must be defined at the table level instead of the column level.

One of the LONG columns must be changed to a VARCHAR2 or CLOB.

The NOT NULL constraint on ENAME must be defined at the column level instead of the table level.

The primary key constraint on BMP_ID must have a name.

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